如何用python求100以内的素数？

num=[];

i=2

for i in range(2,100):

   j=2

   for j in range(2,i):

      if(i%j==0):

         break

   else:

      num.append(i)

print(num)

import math

def func_get_prime(n):

  return filter(lambda x: not [x%i for i in range(2, int(math.sqrt(x))+1) if x%i ==0], range(2,n+1))

print func_get_prime(100)

[2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]