如何在Python中对dicts列表进行排序

解决：以下是如何对数据进行排序。（它只有一行Python，但很难记住如何做到这一点。）

DATA是mongoDB组函数的输出。我想按照这个列表来排序'ups_ad'。

from pprint import pprintDATA = [
    {u'avg': 2.9165000000000001,
     u'count': 10.0,
     u'total': 29.165000000000003,
     u'ups_ad': u'10.194.154.49:80'},
    {u'avg': 2.6931000000000003,
     u'count': 10.0,
     u'total': 26.931000000000001,
     u'ups_ad': u'10.194.155.176:80'},
    {u'avg': 1.9860909090909091,
     u'count': 11.0,
     u'total': 21.847000000000001,
     u'ups_ad': u'10.195.71.146:80'},
    {u'avg': 1.742818181818182,
     u'count': 11.0,
     u'total': 19.171000000000003,
     u'ups_ad': u'10.194.155.48:80'}
    ]data_sorted = sorted(DATA, key=lambda item: item['ups_ad'])pprint(data_sorted)

结果：

[{u'avg': 2.9165000000000001,
  u'count': 10.0,
  u'total': 29.165000000000003,
  u'ups_ad': u'10.194.154.49:80'},
 {u'avg': 2.6931000000000003,
  u'count': 10.0,
  u'total': 26.931000000000001,
  u'ups_ad': u'10.194.155.176:80'},
 {u'avg': 1.742818181818182,
  u'count': 11.0,
  u'total': 19.171000000000003,
  u'ups_ad': u'10.194.155.48:80'},
 {u'avg': 1.9860909090909091,
  u'count': 11.0,
  u'total': 21.847000000000001,
  u'ups_ad': u'10.195.71.146:80'}]

参考文献：

HowTo / Sorting - PythonInfo Wiki

排序的内置函数 - Python文档