python列表如何分成大小均匀的块

def chunks(lst, n):

    """Yield successive n-sized chunks from lst."""

    for i in range(0, len(lst), n):

        yield lst[i:i + n]

import pprint

pprint.pprint(list(chunks(range(10, 75), 10)))

[[10, 11, 12, 13, 14, 15, 16, 17, 18, 19],

 [20, 21, 22, 23, 24, 25, 26, 27, 28, 29],

 [30, 31, 32, 33, 34, 35, 36, 37, 38, 39],

 [40, 41, 42, 43, 44, 45, 46, 47, 48, 49],

 [50, 51, 52, 53, 54, 55, 56, 57, 58, 59],

 [60, 61, 62, 63, 64, 65, 66, 67, 68, 69],

 [70, 71, 72, 73, 74]]

def chunks(lst, n):

    """Yield successive n-sized chunks from lst."""

    for i in xrange(0, len(lst), n):

        yield lst[i:i + n]

[lst[i:i + n] for i in range(0, len(lst), n)]

Python 2 版本：

[lst[i:i + n] for i in xrange(0, len(lst), n)]