class cnumber:
cdict = {}
gdict = {}
xdict = {}
def __init__(self):
self.cdict = {1: u'', 2: u'拾', 3: u'佰', 4: u'仟'}
self.xdict = {1: u'元', 2: u'万', 3: u'亿', 4: u'兆'} # 数字标识符
self.gdict = {0: u'零', 1: u'壹', 2: u'贰', 3: u'叁', 4: u'肆', 5: u'伍', 6: u'陆', 7: u'柒', 8: u'捌', 9: u'玖'}
def csplit(self, cdata): # 拆分函数，将整数字符串拆分成[亿，万，仟]的list
g = len(cdata) % 4
csdata = []
lx = len(cdata) - 1
if g > 0:
csdata.append(cdata[0:g])
k = g
while k <= lx:
csdata.append(cdata[k:k + 4])
k += 4
return csdata
def cschange(self, cki): # 对[亿，万，仟]的list中每个字符串分组进行大写化再合并
lenki = len(cki)
i = 0
lk = lenki
chk = u''
for i in range(lenki):
if int(cki[i]) == 0:
if i < lenki - 1:
if int(cki[i + 1]) != 0:
chk = chk + self.gdict[int(cki[i])]
else:
chk = chk + self.gdict[int(cki[i])] + self.cdict[lk]
lk -= 1
return chk
def cwchange(self, data):
cdata = str(data).split('.')
cki = cdata[0]
if len(cdata) == 1:
i = 0
chk = u''
cski = self.csplit(cki) # 分解字符数组[亿，万，仟]三组List:['0000','0000','0000']
ikl = len(cski) # 获取拆分后的List长度
# 大写合并
for i in range(ikl):
if self.cschange(cski[i]) == '': # 有可能一个字符串全是0的情况
chk = chk + self.cschange(cski[i]) # 此时不需要将数字标识符引入
else:
chk = chk + self.cschange(cski[i]) + self.xdict[ikl - i] # 合并：前字符串大写+当前字符串大写+标识符
chk = chk + u'整'
else:
i = 0
chk = u''
cski = self.csplit(cki) # 分解字符数组[亿，万，仟]三组List:['0000','0000','0000']
ikl = len(cski) # 获取拆分后的List长度
# 大写合并
for i in range(ikl):
if self.cschange(cski[i]) == '': # 有可能一个字符串全是0的情况
chk = chk + self.cschange(cski[i]) # 此时不需要将数字标识符引入
else:
chk = chk + self.cschange(cski[i]) + self.xdict[ikl - i] # 合并：前字符串大写+当前字符串大写+标识符
# 处理小数部分
ckj = cdata[1]
lenkj = len(ckj)
if lenkj == 1: # 若小数只有1位
if int(ckj[0]) == 0:
chk = chk + u'整'
else:
chk = chk + self.gdict[int(ckj[0])] + u'角整'
else: # 若小数有两位的四种情况
if int(ckj[0]) == 0 and int(ckj[1]) != 0:
chk = chk + u'零' + self.gdict[int(ckj[1])] + u'分'
elif int(ckj[0]) == 0 and int(ckj[1]) == 0:
chk = chk + u'整'
elif int(ckj[0]) != 0 and int(ckj[1]) != 0:
chk = chk + self.gdict[int(ckj[0])] + u'角' + self.gdict[int(ckj[1])] + u'分'
else:
chk = chk + self.gdict[int(ckj[0])] + u'角整'
return chk
if __name__ == '__main__':
pt = cnumber()
print(pt.cwchange('14524')) # 壹万肆仟伍佰贰拾肆元整
