python列表如何去除元素

>>> str=[1,2,3,4,5,2,6]

>>> str.remove(2)

>>> str

[1, 3, 4, 5, 2, 6]

>>> str=[0,1,2,3,4,5,6]

>>> str.pop(1) #pop删除时会返回被删除的元素

>>> str

[0, 2, 3, 4, 5, 6]

>>> str2=['abc','bcd','dce']

>>> str2.pop(2)

'dce'

>>> str2

['abc', 'bcd']

>>> str=[1,2,3,4,5,2,6]

>>> del str[1]

>>> str

[1, 3, 4, 5, 2, 6]

s1 = (1, 2, 3, 4, 5, 6)

s2 = (2, 3, 5)

s3 = []

for i in s1:

    if i not in s2:

        s3.append(i)

print('s1_1:', s1)

s1 = s3

print('s2:', s2)

print('s3:', s3)

print('s1_2:', s1)