python如何获取更多时间戳精度

调度任务中常常要用到精确的时间，如果获取的13位时间戳不够准确的话，会造成数据的重复或者缺失

通常的不准确的13位时间戳的获取方式(秒*1000)

import time
millis = int(round(time.time() * 1000))
print millis

准确的13位时间戳获取（微妙/1000）

# -*- coding: utf-8 -*-
 
import datetime
import time
 
"""
    获取精确毫秒数时间戳、   
"""
def get_seconds():
 
    datetime_object = datetime.datetime.now()
    now_timetuple = datetime_object.timetuple()
    now_second = time.mktime(now_timetuple)
    mow_millisecond = long(now_second*1000 + datetime_object.microsecond/1000)
    print "timetuple-- "+ str(now_timetuple)
    print "datimeobject-- " + str(datetime_object)
    print "second-- " + str(now_second)
    print "millisecond-- " + str(mow_millisecond)
 
 
if __name__ == "__main__":
 
    get_seconds()

结果

timetuple-- time.struct_time(tm_year=2018, tm_mon=12, tm_mday=3, tm_hour=11, tm_min=55, tm_sec=6, tm_wday=0, 
tm_yday=337, tm_isdst=-1)
datimeobject-- 2018-12-03 11:55:06.254679
second-- 1543809306.0
millisecond-- 1543809306254

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