python如何过滤数字

import re

L = [u'小明', 'xiaohong', '12', 'adf12', '14']

for i in range(len(L)):

  if re.findall(r'^[^\d]\w+',L[i]):

    print re.findall(r'^\w+$',L[i])[0]

  elif isinstance(L[i],unicode):

    print L[i]

L = [ 'xiaohong', '12', 'adf12', '14',u'晓明']

for x in L:

  try:

    int(x)

  except:

    print x

L = [ 'xiaohong', '12', 'adf12', '14',u'晓明']

#对于python3来说同样还可以使用string.isnumeric()方法

for x in L:

  if not x.isdigit():

    print x

In [24]: import string

In [25]: astring = '12313213215just for 32 test 1306436'

In [26]: astring.strip(string.digits)

Out[26]: 'just for 32 test '

In [27]: astring.rstrip(string.digits)

Out[27]: '12313213215just for 32 test '

In [30]: astring.lstrip(string.digits)

Out[30]: 'just for 32 test 1306436'

#注意

In [31]: astring

Out[31]: '12313213215just for 32 test 1306436'

In [32]: astring.strip('0123456')

Out[32]: 'just for 32 test '