python怎么打印异常原因

print("test2") 

try:

    x = 1

    y = 0

    z= x/y

except:#捕获所有异常

    print('there is problem')

else:

    print('no problem')

finally:

    print('end test2')

try:

    正常的操作except(Exception1[, Exception2[,...ExceptionN]]]):

   发生以上多个异常中的一个，执行这块代码else:

    如果没有异常执行这块代码

print('test3')

try:

    x = 1

    y = 0

    z= x/y

except (NameError,ZeroDivisionError):

    print("problem is (NameError,ZeroDivisionError)")

except (RuntimeError, TypeError):

    print("problem is (RuntimeError, TypeError)")

except:

    print("problem")

    raise

else:

    print("no problem")

finally:

    print('end test3')

import sys

try:

    f = open('myfile.txt')

    s = f.readline()

    i = int(s.strip())

# except OSError as err:

#     print("OS error: {0}".format(err))

except ValueError:

    print("Could not convert data to an integer.")

except:

    print("Unexpected error:", sys.exc_info()[0])

    for i in sys.exc_info():

        print(i)

    raise Exception('line xxx')

finally:

    print("end")